JEE MATHEMATICS MCQ: TRIGONOMETRIC EQUATIONS

1 Easy

1 of 1

Application +4 | -1

\sin ^2 \theta+3 \cos \theta-2=0

, then

\cos ^3 \theta+\sec ^3 \theta=\ldots \ldots, \theta \neq(2 k+1) \frac{\pi}{2}, k \in Z

View answer and explanation

Correct option: A

Option C (

y-x

) is correct because simplifying the given expression using trigonometric identities leads to

y-x

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\mathrm{X}

\theta \rightarrow \frac{\pi}{2}

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0 < x < \pi

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