The specific heat of water $ = 4200\,\,\,{\rm{J}}\,\,{\rm{k}}{{\rm{g}}^{ - 1}}\,{{\rm{K}}^{ - 1}}$ and the latent heat of ice $ = 3.4 \times {10^5}\,\,{\rm{J}}\,\,{\rm{k}}{{\rm{g}}^{ - 1}}.$ 100 g of ice at $0^\circ {\rm{C}}$ is placed in 200 g of water at $25^\circ {\rm{C}}{\rm{.}}$ The amount of ice that will melt as the temperature of water reaches $0^\circ {\rm{C}}$ is close to (in grams)

NEET UG PHYSICS MCQ: THERMAL PROPERTIES OF MATTER

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Application +4 | -1

The specific heat of water

= 4200\,\,\,\mathrm{J}\,\,\mathrm{k}{\mathrm{g}^{ - 1}}\,{\mathrm{K}^{ - 1}}

and the latent heat of ice

= 3.4 \times {10^5}\,\,\mathrm{J}\,\,\mathrm{k}{\mathrm{g}^{ - 1}}.

100 g of ice at

0^\circ \mathrm{C}

is placed in 200 g of water at

25^\circ \mathrm{C}\mathrm{.}

The amount of ice that will melt as the temperature of water reaches

0^\circ \mathrm{C}

is close to (in grams)

View answer and explanation

Correct option: D

61.7

Option D (61.7) is correct because it calculates the amount of ice that melts by equating the heat lost by the water to the heat gained by the ice to melt.

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is placed in an insulation box of wall thickness

1 \mathrm{~cm}

. The box keeping the ice cube at

0^{\circ} \mathrm{C}

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. The rate of melting of ice is approximately.

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and thermal conducting of insulation wall is

\left. {0.05{\text{W}}{{\text{m}}^{ - 1}}^\circ {{\text{C}}^{ - 1}}} \right)

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2 \times 10^5 \mathrm{~J} / \mathrm{sm}^2

at temp. of

127^{\circ} \mathrm{C}

. The temp of black body at which rate becomes

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\sigma

+ \frac{1}{2}

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