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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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Analyzing +4 | -1
If log⁡ab−c=log⁡bc−a=log⁡ca−b,\frac{{\log a}}{{b - c}} = \frac{{\log b}}{{c - a}} = \frac{{\log c}}{{a - b}}, then aabbcc={a^a}{b^b}{c^c} =
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Correct option: B
1
Option B (1) is correct because when log⁡ab−c=log⁡bc−a=log⁡ca−b=λ\frac{{\log a}}{{b - c}} = \frac{{\log b}}{{c - a}} = \frac{{\log c}}{{a - b}} = \lambda, then aabbcc=1{a^a}{b^b}{c^c} = 1.

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