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JEE MATHEMATICS MCQ: ELLIPSE

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Application +4 | -1
If xa+yb=2\frac{x}{a} + \frac{y}{b} = \sqrt 2 touches the ellipse x2a2+y2b2=1\frac{{{x^2}}}{{{a^2}}} + \frac{{{y^2}}}{{{b^2}}} = 1 then the eccentric angle of the point of contact is equal to
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Correct option: C
450{45^0}
The correct answer is C (450{45^0}) because it represents the eccentric angle of the point of contact of the line and the ellipse.

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