JEE PHYSICS MCQ: SYSTEM OF PARTICLES

1 Medium

1 of 1

Application +4 | -1

The moment of inertia of a uniform circular disc of radius

R

and mass

M

about an axis passing from the edge of the disc and normal to the disc is:

View answer and explanation

Correct option: C

\frac{3}{2} {M} {R}^2

Option C (

\frac{3}{2}MR^2

) is correct because it is calculated using the parallel axis theorem.

More Questions from SYSTEM OF PARTICLES

Practice All Chapter MCQs →

\mathrm{AB}

\mathrm{L}

\mu(x)=a+\frac{b x}{L}

x

\mathrm{A}

\mathrm{CM}

\left(\frac{7}{12}\right) \mathrm{L}

\mathrm{A}

\mathrm{b}

1.0 \mathrm{~g}

8 \mathrm{~cm}

\omega = {t^4} + 2{t^3}

t = 1\,sec

\left( {rad\,{s^{ - 2}}} \right)