JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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1+\frac{\log _{e} x}{1 !}+\frac{\left(\log _{e} x\right)^{2}}{2 !}+\frac{\left(\log _{e} x\right)^{3}}{3 !}+\cdots \infty=

View answer and explanation

Correct option: B

x

Option B (

x

) is correct because the given series is the Taylor series expansion of

e^y

where

y = \log_e x

, so the sum is

e^{\log_e x} = x

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