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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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The angle of elevation of the top CC of a vertical tower CDC D of height hh from a point AA in the horizontal plane is 45∘45^{\circ} and from a point BB at a distance aa from AA on the line making an angle 30∘30^{\circ} with ADA D, it is 60∘60^{\circ}, then
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Correct option: C
a=h(3−1)a=h(\sqrt{3}-1)
Option C (a=h(3−1)a=h(\sqrt{3}-1)) is correct because it is derived by using trigonometric relationships and the sine rule in the given geometric setup.

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