JEE MATHEMATICS MCQ: PERMUTATIONS

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How many nine digit numbers can be formed by using the digits

2,2,3,3,5,5,8,8,8

so that the odd digits occupy even positions?

View answer and explanation

Correct option: D

The correct answer is 60 because the odd digits must occupy the even positions, and the even digits must occupy the odd positions. The number of arrangements is calculated by multiplying the arrangements of odd digits in even places and even digits in odd places.

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