JEE CHEMISTRY MCQ: HYDROCARBONS

1 Hard

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Analyzing +4 | -1

The isomer of

\mathrm{C}_6 \mathrm{H}_{14},

which will give maximum number of monochloroderivative is

View answer and explanation

Correct option: B

2-methylpentane

Option C (inorganic graphite) is correct because diborane reacts with ammonia at high temperatures to form boron nitride, which has a graphite-like structure.

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\mathrm{Ca}{\mathrm{C}_2} + {\mathrm{H}_2}\mathrm{O} \to X\xrightarrow{{{\mathrm{O}_3}/\frac{{{\mathrm{H}_2}\mathrm{O}}}{{\mathrm{O}{\mathrm{H}^ + }}}}}\mathrm{HCOOH} + \mathrm{HCOOH},X\;\mathrm{is}

In benzene, there is a delocalisation of π-electrons. Hence, each π-electron is attached by….carbon nuclei. Which statement is false? Assertion (A) In comparison to ethyl chloride, it is not easy to carry outnucleophilic substitution on vinyl chloride.

Reason (R) Vinyl group is an electron donating. If 2-oxopropanal and methanal are obtained by the reductive ozonolysis of compound (A), then the number of

\sigma

-bonds presents in Fischer-Tropsch process is used in the manufacture of: