Back to d & f- BLOCK ELEMENTS

JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

1 Medium

1 of 1

Application +4 | -1

The magnetic moment of a transition metal ion is

\sqrt {15\;}

BM. Therefore, the number of unpaired electrons present in it, is

View answer and explanation

Correct option: A

3

Option A (3) is correct because the number of unpaired electrons (n) is calculated using the formula

\mathrm{\mu } = \sqrt {n(n + 2)}

and solving for n when

\mathrm{\mu } = \sqrt{15}

.

More Questions from d & f- BLOCK ELEMENTS

Practice All Chapter MCQs →

Mercury is transported in metal containers made of: Cadmipone is a mixture of: The number of element from the following that do not belong to lanthanoids is :
Eu, Cm, Er, Tb, Yb and Lu Statement-I:

{Sm}^{3+}

{Dy}^{3+}

have same colour (yellow).

Statement-II: Both ions are having same number of unpaired electrons. The most common oxidation state of Lanthanoid
elements is +3. Which of the following is likely to
also form other oxidation state? A mixture of

\mathrm{Ti}{\mathrm{O}_2}

\mathrm{BaS}{\mathrm{O}_4}