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JEE MATHEMATICS MCQ: DIFFERENTIAL EQUATIONS

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Analyzing +4 | -1
The normal at any point P(x,y)P(x, y) of a curve meets xx - and yy-axes in AA and BB, respectively. If OO is the origin and OAO A and OBO B are the algebraic intercepts of the normal at PP such that 1OA+1OB=1\frac{1}{O A}+\frac{1}{O B}=1 then the equation of the curve is [given that (5,4)(5,4) is a point on the curve]
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Correct option: D
(x−1)2+(y−1)2=25(x-1)^2+(y-1)^2=25
Option D ((x−1)2+(y−1)2=25(x-1)^2+(y-1)^2=25) is correct because it represents the equation of the curve obtained by solving the given differential equation and using the point (5,4).

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