JEE PHYSICS MCQ: WAVE OPTICS

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Application +4 | -1

In a Young’s experiment, one of the slits is covered with a transparent sheet of thickness

3.6 \times {10^{ - 3}}\;cm

due to which position of central fringe shifts to a position originally occupied by

{30^{th}}

fringe. The refractive index of the sheet, if

\lambda = 6000\mathop \mathrm{A}\limits^ \circ

, is

View answer and explanation

Correct option: A

1.5

Option A (1.5) is correct because the refractive index is calculated using the shift in fringe position due to the transparent sheet in Young's experiment.

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