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JEE MATHEMATICS MCQ: 2D GEOMETRY SYSTEM

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Application +4 | -1
The locus of the mid-point of the distance between the axes of the variable line xcos⁡α+ysin⁡α=px \cos \alpha+y \sin \alpha=p, where pp is constant, is
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Correct option: B
1x2+1y2=4p2\frac{1}{x^{2}}+\frac{1}{y^{2}}=\frac{4}{p^{2}}
Option B (1x2+1y2=4p2\frac{{1}}{{x^{2}}}+\frac{{1}}{{y^{2}}}=\frac{{4}}{{p^{2}}}) is correct because it represents the locus of the midpoint of the segment between the axes of the given line.

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