If $f$ be a function such that $f\left( 9 \right) = 9$ and $f'\left( 9 \right) = 3$, then $\mathop {\lim }\limits_{x \to 9} \frac{{\sqrt {f\left( x \right)} - 3}}{{\sqrt x - 3}}$ is equal to

JEE MATHEMATICS MCQ: LIMITS

1 Easy

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Application +4 | -1

f

be a function such that

f\left( 9 \right) = 9

and

f'\left( 9 \right) = 3

, then

\lim\limits_{x \to 9} \frac{{\sqrt {f\left( x \right)} - 3}}{{\sqrt x - 3}}

is equal to

View answer and explanation

Correct option: B

Option B (3) is correct because the limit simplifies to 3 after multiplying by the conjugate and using the given values of

f(9)

and

f'(9)

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