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JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1
lim⁡x→∞cot⁡−1(x+1−x)sec⁡−1{(2x+1x−1)x}\lim \limits_{{x \rightarrow \infty}} \frac{\cot ^{-1}(\sqrt{x+1}-\sqrt{x})}{\sec ^{-1}\left\{\left(\frac{2 x+1}{x-1}\right)^x\right\}} is equal to
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Correct option: A
1
Option A (1) is correct because as x approaches infinity, the numerator approaches cot⁡−1(0)=π2\cot^{-1}(0) = \frac{\pi}{2} and the denominator approaches sec⁡−1(∞)=π2\sec^{-1}(\infty) = \frac{\pi}{2}, resulting in a limit of 1.

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