JEE MATHEMATICS MCQ: LIMITS

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Analyzing +4 | -1

The value of

\lim\limits_{n \to \infty } \frac{1}{{1.3}} + \frac{1}{{3.5}} + \frac{1}{{5.7}} + ... + \frac{1}{{\left( {2n - 1} \right)\left( {2n + 1} \right)}}

View answer and explanation

Correct option: A

\frac{1}{2}

Option A (

\frac{1}{2}

) is correct because the given series telescopes, and the limit as n approaches infinity is

\frac{1}{2}

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