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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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If bn=∫0π2cos⁡2nxsin⁡x  dx,    n∈N,{b_n} = \int_0^{\frac{\pi }{2}} {\frac{{{{\cos }^2}nx}}{{\sin x}}} \,\,dx,\,\,\,\,n \in \mathbb{N}, then,
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Correct option: D
1b3−b2,1b4−b3,1b5−b4\frac{1}{{{b_3} - {b_2}}},\frac{1}{{{b_4} - {b_3}}},\frac{1}{{{b_5} - {b_4}}} are in an A.P. with common difference –2
Option D (1b3−b2,1b4−b3,1b5−b4\frac{1}{{{b_3} - {b_2}}},\frac{1}{{{b_4} - {b_3}}},\frac{1}{{{b_5} - {b_4}}} are in an A.P. with common difference –2) is correct because by evaluating the integral and finding the differences between consecutive terms, we can show that the reciprocals form an arithmetic progression.

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