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JEE PHYSICS MCQ: NUCLEI

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Understanding +4 | -1
For a nucleus ZAX{ }_Z^A X having mass number A{A} and atomic number Z{Z}

A. The surface energy per nucleon (bs)=a1A2/3\left(b_s\right)=a_1 A^{2 / 3}

B. The coulomb contribution to the binding energy bc=−a2Z(Z−1)A4/3b_c=-a_2 \frac{Z(Z-1)}{A^{4 / 3}}

C. The volume energy bv=a3Ab_v=a_3 A

D. Decrease in the binding energy is proportional surface area.

E. While estimating the surface energy, it is assumed that each nucleon interacts with 12 nucleons,
( a1,a2a_1, a_2 and a3a_3 are constants)

Choose the most appropriate answer form the options given below;
View answer and explanation
Correct option: A
C, D only
Option C (A, D only) is correct because the surface energy is inversely proportional to A(1/3), and the decrease in binding energy is proportional to surface area.

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