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JEE CHEMISTRY MCQ: HALOALKANES AND HALO ARENES

1 Easy
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Application +4 | -1
The major product formed in the following reaction :

CH3CH(Cl)CH2βˆ’CH2OH⟢ aq.Β KOH{CH}_3 {CH}({Cl}) {CH}_2-{CH}_2 {OH} \stackrel{\text { aq. } {KOH}}{\longrightarrow} is :
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Correct option: D
CH3βˆ’CH∣OHβˆ’CH2βˆ’CH2OHC{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {OH} \end{array}} - C{H_2} - C{H_2}OH
Option D (CH3βˆ’CH∣OHβˆ’CH2βˆ’CH2OHC{H_3} - \mathop {CH}\limits_{\begin{array}{cccccccccccccccccccc} | \\ {OH} \\ \end{array}} - C{H_2} - C{H_2}OH) is correct because the aqueous KOH will substitute the chlorine atom with a hydroxyl group.

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