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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Analyzing +4 | -1
If f(1x)+x2f(x)=0,x>0f\left(\frac{1}{x}\right)+x^2 f(x)=0, x>0 and I=∫1/xxf(t)dt,12≤x≤2I=\int_{1 / x}^x f(t) d t, \frac{1}{2} \leq x \leq 2, then II is equal to
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Correct option: C
0
Option C (0) is correct because the integral evaluates to zero due to the given functional equation and properties of definite integrals.

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