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JEE MATHEMATICS MCQ: INCREASING & DECREASING

1 Hard
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Analyzing +4 | -1
If the function f(x)=(2a−3)(x+2sin⁡3)+(a−1)(sin⁡4x+cos⁡4x)+log⁡2f\left( x \right) = \left( {2a - 3} \right)\left( {x + 2\sin 3} \right) + \left( {a - 1} \right)\left( {{{\sin }^4}x + {{\cos }^4}x} \right) + \log 2 does not possess critical points, then
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Correct option: A
a∈(−∞,  4/3)∪(2,  ∞)a \in \left( { - \infty ,\;4/3} \right) \cup \left( {2,\;\infty } \right)
Option A (a∈(−∞,4/3)∪(2,∞)a \in (-\infty, 4/3) \cup (2, \infty)) is correct because for the function to have no critical points, the derivative must not equal zero, leading to the given range for 'a'.

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