NEET UG PHYSICS MCQ: MOTION IN PLANE

1 Hard

1 of 1

Application +4 | -1

A ship

A

sailing due east with a velocity of

10 km / h

happens to appear sailing due north with a velocity of

5 km / h

, to a person, sitting in a moving ship

B.

Determine the velocity (absolute) of ship

B.

View answer and explanation

Correct option: A

5 \sqrt{5} km / h , \tan ^{-1}(1 / 2) S

of E

Option A (

5 \sqrt{5} km / h , \tan ^{-1}(1 / 2) S

of E) is correct because it accurately calculates the absolute velocity of ship B by considering the relative velocity and the velocity of ship A.

More Questions from MOTION IN PLANE

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\mathrm{\vec a}\,and\,\mathrm{\vec b}

\mathrm{\vec a}\,and\,\mathrm{\vec b}

\overrightarrow P \,\,.\,\,\overrightarrow Q = 0\,and\,\overrightarrow P \,\, \times \,\,\overrightarrow Q = 0

\overrightarrow Q \,and\,\overrightarrow R

\vec{A}=3 \hat{i}+4 \hat{j}

\vec{B}=6 \hat{i}+8 \hat{j}

A

B

\overrightarrow{\mathrm{A}}

\overrightarrow{\mathrm{B}}

{\cot ^{ - 1}}\left( 2 \right)