One bisector of the angle between the lines given by $a(x-1)^2+2 h(x-1) y+b y^2=0$ is $2 x+y-2=0$. The equation of the other bisector is

JEE MATHEMATICS MCQ: PAIR OF STRAIGHT LINES

1 Easy

1 of 1

Application +4 | -1

One bisector of the angle between the lines given by

a(x-1)^2+2 h(x-1) y+b y^2=0

2 x+y-2=0

. The equation of the other bisector is

View answer and explanation

Correct option: C

x-2 y-1=0

Option C (

x-2y-1=0

) is correct because the angle bisectors are perpendicular, and the other bisector must pass through (1,0) and be perpendicular to the given bisector.

More Questions from PAIR OF STRAIGHT LINES

Practice All Chapter MCQs →

a x^2+2 h x y+b y^2+2 g x+2 f y+c=0

represents parallel straight lines, then Image of the point

(-1,3)

with respect to the line

y=2 x

is If the pair of lines represented by

a x^2+2 h x y+b y^2+2 g x+2 f y+c=0

intersect on

y

-axis, then If the sum of the slopes of the lines given by

4 x^2+2 \lambda x y-7 y^2=0

is equal to the product of the slopes, then

\lambda

is equal to The equation

3 x^2+2 h x y+3 y^2=0

represents a pair of straight lines passing through the origin. The two lines are The value of

h

for which

3 x^2-3 h x y+4 y^2=0

represents a pair of coincident lines are