A particle is projected vertically from the ground takes time $t_1=1 \mathrm{~s}$ upto point ${A},\,\,t_2=3 \mathrm{~s}$ from point ${A}$ to $B$, and time $t_3$ $=4 \mathrm{~s}$ from point $B$ to highest point. Find the height of the middle point of $A$ and $B$ from the ground.

JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A particle is projected vertically from the ground takes time

t_1=1 \mathrm{~s}

upto point

{A},\,\,t_2=3 \mathrm{~s}

from point

{A}

B

, and time

t_3

=4 \mathrm{~s}

from point

B

to highest point. Find the height of the middle point of

A

and

B

from the ground.

View answer and explanation

Correct option: A

60 m

Option A (60 m) is correct because it is the height of the midpoint of A and B calculated using kinematics and the given time intervals.

Practice All Chapter MCQs →

\mathrm{g}

\mathrm{h}

\mathrm{u}

\frac{\mathrm{h}}{\mathrm{u}}

4.9 \mathrm{~m}

(\mathrm{g}=9.8 \mathrm{~m} / \mathrm{s}^2)

t

(t+1)

120 \mathrm{~m}

50 \mathrm{~m} / \mathrm{s}

\mathrm{m}

(t+2)