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JEE PHYSICS MCQ: UNITS & MEASUREMENTS

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Application +4 | -1
In an experiment four quantities a,b,ca, b, c and dd are measured with percentage error 2%,3%,4%2 \%, 3 \%, 4 \% and 1%1 \% respectively. Quantity PP is calculated as follows; P=a3b2cdP=\frac{a^3 b^2}{c d}. Percentage error in PP is;
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Correct option: D
17%17 \%
Option D (17%17 \%) is correct because the percentage error in P is calculated by summing the absolute values of the percentage errors in a, b, c, and d, each multiplied by its exponent in the formula for P.

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