A body of mass x kg is moving with a velocity of $100{\rm{m}}{{\rm{s}}^{ - 1}}$. Its de-Broglie wavelength is $6.62 \times {10^{ - 35}}$. Hence, x is ($h = 6.62 \times {10^{ - 34}}{\rm{Js}}$)

JEE CHEMISTRY MCQ: STRUCTURE OF ATOM

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A body of mass x kg is moving with a velocity of

100\mathrm{m}{\mathrm{s}^{ - 1}}

. Its de-Broglie wavelength is

6.62 \times {10^{ - 35}}

. Hence, x is (

h = 6.62 \times {10^{ - 34}}\mathrm{Js}

)

View answer and explanation

Correct option: A

0.1 kg

The correct answer is A (0.1 kg) because the mass is calculated using the de Broglie wavelength formula.

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n^{\text {th }}

\mathrm{A}

\times 10^{12}

\frac{1}{{ }^{\prime} \mathrm{B}^{\prime}}

\ell = 1,\,\,m = 0

1.25 \times {10^{ - 13}} \times {A^{1/3}}\mathrm{cm}.