Skip to main content
Back to LIMITS

JEE MATHEMATICS MCQ: LIMITS

1 Easy
1 of 1
Analyzing +4 | -1
If f′(2)=6f^{\prime}(2)=6 and f′(1)=4f^{\prime}(1)=4, then

lim⁡h→0f(2h+2+h2)−f(2)f(h−h2+1)−f(1)\lim \limits_{{h \rightarrow 0}} \frac{f\left(2 h+2+h^2\right)-f(2)}{f\left(h-h^2+1\right)-f(1)}
View answer and explanation
Correct option: D
is equal to 3
Option D (is equal to 3) is correct because the limit can be evaluated using L'Hopital's rule, resulting in the value 3.

More Questions from LIMITS

Practice All Chapter MCQs →
Type at least 2 characters or jump directly:
🔓

Save your learning progress

Sign in with a free account to save your practice answers and quiz results, then return to them when you revise.