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JEE MATHEMATICS MCQ: DIFFERENTIATION

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If x2+y2=1x^2+y^2=1, then
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Correct option: B
yy′′+(y′)2+1=0y y^{\prime \prime}+\left(y^{\prime}\right)^2+1=0
Option B is correct because it is the result of differentiating the given implicit equation twice and rearranging the terms.

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