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JEE CHEMISTRY MCQ: d & f- BLOCK ELEMENTS

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Understanding +4 | -1
When KI\mathrm{KI} (excess) is added to the following solutions

(i) CuSO4\mathrm{CuSO}_4

(ii) HgCl2\mathrm{HgCl}_2

(iii) Pb(NO3)2\mathrm{Pb}\left(\mathrm{NO}_3\right)_2

separately:
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Correct option: D
A white precipitate of Cu2I2\mathrm{Cu}_2 \mathrm{I}_2 in I\mathrm{I}, an orange precipitate dissolving to HgI42−\mathrm{HgI}_4^{2-} in II\mathrm{II} and a yellow precipitate of PbI2\mathrm{PbI}_2 in III
Option D (A white precipitate of Cu2I2\mathrm{Cu}_2 \mathrm{I}_2 in I\mathrm{I}, an orange precipitate dissolving to HgI42−\mathrm{HgI}_4^{2-} in II\mathrm{II} and a yellow precipitate of PbI2\mathrm{PbI}_2 in III) is correct because it accurately describes the reactions and precipitates formed when excess KI is added to CuSO4, HgCl2, and Pb(NO3)2 solutions.

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