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NEET UG CHEMISTRY MCQ: AMINES

1 Hard
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Application +4 | -1
CH3CH2Br→aq.KOHΔA  →KMnO4/H+ΔB→NH3ΔC→Br2alkaliD,   ′D′\mathrm{C}{\mathrm{H}_3}\mathrm{C}{\mathrm{H}_2}\mathrm{Br}\mathop {\mathop \to \limits^{aq.\mathrm{KOH}} }\limits_\Delta A\mathrm{\;}\mathop {\mathop \to \limits^{\mathrm{KMn}{\mathrm{O}_4}/{\mathrm{H}^ + }} }\limits_\Delta B\mathop {\mathop \to \limits^{\mathrm{N}{\mathrm{H}_3}} }\limits_\Delta C\mathop {\mathop \to \limits^{\mathrm{B}{\mathrm{r}_2}} }\limits_{\mathrm{alkali}} D,\,\,\,'D' is
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Correct option: C
CH3NH2\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}
Option C (CH3NH2\mathrm{C}{\mathrm{H}_3}\mathrm{N}{\mathrm{H}_2}) is correct because the series of reactions converts ethyl bromide to ethyl alcohol, then to acetic acid, then to acetamide, and finally to methylamine via Hoffmann degradation.

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