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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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The sum to nn terms of the series 11+103+1005+…11+103+1005+\ldots. Is
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Correct option: C
109(10n−1)+n2\frac{10}{9}\left(10^n-1\right)+n^2
Option C (109(10n−1)+n2\frac{{10}}{{9}}(10^n-1)+n^2) is correct because it is derived by separating the series into a geometric progression and an arithmetic progression.

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