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JEE MATHEMATICS MCQ: LIMITS

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Understanding +4 | -1
lim⁡x→1sin⁡∣∣∣x∣−2∣−3∣\lim \limits_{{x \rightarrow 1}} \sin |||x|-2|-3| is equal to
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Correct option: A
sin⁡2\sin 2
Option A (sin⁡2\sin 2) is correct because the function is continuous, allowing direct substitution to find the limit, resulting in sin⁡∣∣∣1∣−2∣−3∣=sin⁡2\sin|||1|-2|-3| = \sin 2.

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