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JEE MATHEMATICS MCQ: PERMUTATIONS

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Four speakers will address a meeting, where speaker

Q

will always speak after speaker

P

. Then, the number of ways in which the order of speakers can be prepared is

View answer and explanation

Correct option: D

12

Option D (12) is correct because in half of the total arrangements, speaker Q will speak after speaker P, so the number of ways is

4!/2 = 12

.

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