JEE MATHEMATICS MCQ: STRAIGHT LINES

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Application +4 | -1

The equation of straight line passing through

(-a, 0)

and making the triangle with axes of area '

T

' is

View answer and explanation

Correct option: B

2 T x-a^2 y+2 a T=0

Option B (

2 T x-a^2 y+2 a T=0

) is correct because it represents the equation of the line passing through (-a, 0) and forming a triangle of area T with the axes.

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x-3 y=p, a x+2 y=q

a x+y=r

\left\{ {a{t_1}{t_2},\;a\left( {{t_1} + {t_2})\} ,\{ a{t_2}{t_3},a({t_2} + {t_3}} \right)} \right\},\;\left\{ {a{t_3}{t_1},\;a\left( {{t_3} + {t_1}} \right)} \right\}

y = 2\;x + 4

6x = 3y + 5

{x^2} + {y^2} + 2xy - 8ax - 8ay - 9{a^2} = 0

(3,8)

x+3 y=7

\left( {{x^2} + 7xy + 2{y^2}} \right)\left( {y - 1} \right) = 0