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JEE PHYSICS MCQ: ELECTRIC FIELDS AND CHARGES

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If the electric field near the earth's surface be 300 V/m300 \mathrm{~V} / \mathrm{m} directed downwards, then the surface density of charge on earth's surface is
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Correct option: C
2.6×10−9C/m22.6 \times 10^{-9} \mathrm{C} / \mathrm{m}^2
Option C (2.6×10−9C/m22.6 \times 10^{-9} \mathrm{C} / \mathrm{m}^2) is correct because it's calculated using the formula relating electric field and surface charge density: E=σ/ε0E = \sigma / \varepsilon_0.

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