NEET UG PHYSICS MCQ: GRAVITATION

1 Easy

1 of 1

Application +4 | -1

The binding energy of a particle of mass

m

with a planet, when it is on the planets surface, is

\frac{1}{2} \mathrm{mv}_0^2

. A tunnel is dug along a diameter of the planet and the particle is dropped into it from the surface, when the body reaches the centre of the planet, its speed is

View answer and explanation

Correct option: B

\frac{v_0}{\sqrt{2}}

Option B (

\frac{v_0}{\sqrt{2}}

) is correct because it's derived from the conservation of energy, considering the potential energy difference between the surface and the center of the planet.

More Questions from GRAVITATION

Practice All Chapter MCQs →

If a particle of mass m is moving in a horizontal circle of radius r with a centripetal force

\left( { - K/{r^2}} \right)

the total energy is Suppose the law of gravitational attraction suddenly changes and becomes an inverse cube law i.e.

F \propto \frac{1}{r^3}

, but still remaining a central force. Then Two satellites A and B go round a planet P is circular orbits having radii 16 R and 2 R respectively. If the speed of satellite A is

6\,m{s^{ - 1}}

the speed of the satellite B will be [in m/s] nearly The total energy of satellite moving with an orbital velocity

v

around the earth is Two satellites of same mass are launched in the same orbit of radius

r

around the earth so as to rotate opposite to each other. If they collide inelastically and stick together as wreckage, the total energy of the system just after collision is Statement-1: There is almost no effect of rotation of earth at poles.
Statement-2: Because rotation of earth is about polar axis.