Which compound will liberate ${\rm{C}}{{\rm{O}}_2}$ from ${\rm{NaHC}}{{\rm{O}}_3}$ solution?

${\rm{C}}{{\rm{H}}_3}{{\rm{N}}^ + }{{\rm{H}}_3}{\rm{C}}{{\rm{L}}^ - }$

${\rm{C}}{{\rm{H}}_3}{\rm{CON}}{{\rm{H}}_2}$

${\rm{C}}{{\rm{H}}_3}{\rm{N}}{{\rm{H}}_2}$

${\left( {{\rm{C}}{{\rm{H}}_3}} \right)_4}{{\rm{N}}^ + }{\rm{O}}{{\rm{H}}^ - }$

NEET UG CHEMISTRY MCQ: AMINES

1 Easy

1 of 1

Application +4 | -1

Which compound will liberate

\mathrm{C}{\mathrm{O}_2}

from

\mathrm{NaHC}{\mathrm{O}_3}

solution?

View answer and explanation

Correct option: D

\mathrm{C}{\mathrm{H}_3}{\mathrm{N}^ + }{\mathrm{H}_3}\mathrm{C}{\mathrm{L}^ - }

Option D (

\mathrm{C}{\mathrm{H}_3}{\mathrm{N}^ + }{\mathrm{H}_3}\mathrm{C}{\mathrm{L}^ - }

) is correct because it is a salt of a weak base (methylammonium chloride) and will react with

\mathrm{NaHC}{\mathrm{O}_3}

to release

\mathrm{C}{\mathrm{O}_2}