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JEE MATHEMATICS MCQ: LIMITS

1 Easy
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Analyzing +4 | -1
Left hand limit and right hand limit of the function x∣x∣+x2\frac{x}{|x|+x^2} at x=0,x=0, are
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Correct option: D
−1,1-1, 1
Option D (-1, 1) is correct because it accurately calculates the left-hand limit and right-hand limit of the given function at x=0.

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