Back to MECHANICAL PROPERTIES OF SOLIDS
JEE PHYSICS MCQ: MECHANICAL PROPERTIES OF SOLIDS
1
Medium
1 of 1
Remembering
+4 | -1
In which year Robert Hooke presented his law of elasticity?
View answer and explanation
Correct option: C
1676
Option C (1676) is correct because Robert Hooke presented his law of elasticity in 1676.
More Questions from MECHANICAL PROPERTIES OF SOLIDS
Practice All Chapter MCQs →
A wire is stretched under a force. If the wire suddenly snaps the temperature of the wire
The increases in length is of a wire of length by the longitudinal stress. Then the stress is proportional to
A steel wire of length and cross sectional area is stretched by under a given load. When the same load is applied to another steel wire of double its length and half of its cross section area, the amount of stretching (extension) is
Assertion: From the relation we can say that, if length of a wire is doubled, its Young's modulus of elasticity will also becomes two times.
Reason: Modulus of elasticity is a material property. A wire can be broken by applying a load of 200 N. The force required to break another wire of the same length and same material, but double in diameter, is Assertion(A): If radius of cylindrical wire is doubled, then this wire can bear four times stress.
Reason(R): By doubling the radius, area of cross-section will become four times.
Reason: Modulus of elasticity is a material property. A wire can be broken by applying a load of 200 N. The force required to break another wire of the same length and same material, but double in diameter, is Assertion(A): If radius of cylindrical wire is doubled, then this wire can bear four times stress.
Reason(R): By doubling the radius, area of cross-section will become four times.