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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Hard
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Application +4 | -1
Let f(x)=∫−2xe(1+t)2dtf(x)=\int\limits_{{-2}}^x e^{(1+t)^2} d t and g(x)=f(h(x))g(x)=f(h(x)) where h(x)h(x) is defined for all x∈Rx \in R. If g′(2)=e4g^{\prime}(2)=e^4 and h′(2)=h^{\prime}(2)= 1 then absolute value of sum of all possible values of h(2)h(2) is
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Correct option: A
2
Option A (2) is correct because it represents the absolute value of the sum of all possible values of h(2) derived from the given conditions and differentiation.

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