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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
Suppose ff is such that f(−x)=−f(x)f\left( { - x} \right) = - f\left( x \right) for every real xx and ∫01f(x)dx=5\int\limits_{0}^1 {f\left( x \right)dx = 5}, then ∫−10f(t)dt=\int\limits_{{ - 1}}^0 {f\left( t \right)dt = }
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Correct option: D
-5
Option D (-5) is correct because the integral of an odd function from -1 to 0 is the negative of the integral from 0 to 1, given that ∫01f(x)dx=5\int_0^1 f(x) dx = 5.

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