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JEE MATHEMATICS MCQ: QUADRATIC EQUATIONS

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Analyzing +4 | -1
If one of the roots of the equation x2+ax+b=0x^2+a x+b=0 and x2+x^2+ bx+a=0b x+a=0 is coincident. Then the numerical value of (a+b)(a+b) is:
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Correct option: B
-1
Option B (-1) is correct because by equating the coincident root in both equations, we can derive that a+b = -1.

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