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JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

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Application +4 | -1
∫0π/2(sin⁡4x+cos⁡4x)dx=\int\limits_{0}^{\pi / 2}\left(\sin ^4 x+\cos ^4 x\right) d x=
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Correct option: B
3π8\frac{3 \pi}{8}
Option B (3π8\frac{3 \pi}{8}) is correct because after using trigonometric identities and integrating, the result is 3π8\frac{3 \pi}{8}.

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