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JEE MATHEMATICS MCQ: SEQUENCE OF SERIES

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If the sum of the first ten terms of the series (135)2+(225)2+(315)2+42+(445)2+……{\left( {1\frac{3}{5}} \right)^2} + {\left( {2\frac{2}{5}} \right)^2} + {\left( {3\frac{1}{5}} \right)^2} + {4^2} + {\left( {4\frac{4}{5}} \right)^2} + \ldots \ldots is 165m\frac{16}{5} m, then mm is equal to
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Correct option: B
101
Option B (101) is correct because after simplifying the series and using summation formulas, the value of m is found to be 101.

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