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JEE MATHEMATICS MCQ: PROPERTIES OF TRIANGLES

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A tower subtends angles θ,2θ,3θ\theta, 2 \theta, 3 \theta at points A,BA, B and CC respectively all lying on a horizontal line through the foot of tower. If ABBC=1+2\frac{A B}{B C}=1+\sqrt{2}, then θ\theta is equal to
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Correct option: A
π8\frac{\pi}{8}
Option A (π8\frac{\pi}{8}) is correct because using trigonometric identities and the given ratio, we can derive that θ=π8\theta = \frac{\pi}{8}.

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