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NEET UG CHEMISTRY MCQ: THERMODYNAMICS

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Application +4 | -1
For vaporization of water at 1 atmospheric pressure, the values of ∆H and ∆S are 40.63 kJ mol−1mo{l^{ - 1}} and 108.8 JK−1mol−1,J{K^{ - 1}}mo{l^{ - 1}}, respectively. The temperature when Gibbs energy change (∆G) for this transformation will be zero, is:
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Correct option: C
373.4 K
Option C (373.4 K) is correct because it is the temperature at which the Gibbs free energy change (∆G) is zero, calculated using the formula ∆G = ∆H - T∆S.

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