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JEE PHYSICS MCQ: MOTION IN A STRAIGHT LINE

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A car, starting from rest, accelerates at the rate f through a distance S, then continues at constant speed for time t and then decelerates at the rate f/2 to come to rest. If the total distance traversed is 15 S, then
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Correct option: C
S=172ft2S = \frac{1}{{72}}f{t^2}
Option C (S=172ft2S = \frac{1}{{72}}f{t^2}) is correct because it is derived from kinematic equations and the total distance equation given the acceleration, constant speed, and deceleration phases.

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