JEE MATHEMATICS MCQ: COMPLEX NUMBERS

1 Easy

1 of 1

Application +4 | -1

Let

{z}_1=6+{i}

and

{z}_2=4-3 {i}

(where

{i}=\sqrt{-1}

). Let

{z}

be a complex number such that

\arg \left(\frac{z-z_1}{z_2-z}\right)=\frac{\pi}{2}

, then

z

satisfies

View answer and explanation

Correct option: B

|z-(5-i)|=\sqrt{5}

Option B,

|z-(5-i)|=\sqrt{5}

, is correct because the locus of

z

is a circle with center at the midpoint of

z_1

and

z_2

and radius equal to half the distance between them.

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\left|\sum\limits_{r=1}^n z_r\right|

(z+a b)^3=a^3

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\alpha, \beta

\gamma

|\alpha-\beta|

{z^2} + {\left| z \right|^2} = 0,

z \in C

2x = - 1 + \sqrt 3 i

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