JEE MATHEMATICS MCQ: PERMUTATIONS

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A team of four students is to be selected from a total of 12 students. Total number of ways in which team can be selected such that two particular students refuse to be together and other two particular students wish to be together only, is equal to

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Correct option: C

226

Option D (None of these) is correct because the total number of ways is 226, which is not among the provided options.

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