$\mathop \smallint \nolimits_0^{\pi /2} \,\,\frac{{\cos \,\,{\rm{\theta }}}}{{\sqrt {4\,\, - \,\,{{\sin }^2}\,\,{\rm{\theta }}} }}\,\,d{\rm{\theta }}$ is equal to

JEE MATHEMATICS MCQ: DEFINITE INTEGRATION

1 Easy

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Application +4 | -1

\int \nolimits_0^{\pi /2} \,\,\frac{{\cos \,\,\mathrm{\theta }}}{{\sqrt {4\,\, - \,\,{{\sin }^2}\,\,\mathrm{\theta }} }}\,\,d\mathrm{\theta }

is equal to

View answer and explanation

Correct option: B

\frac{\mathrm{\pi }}{6}

Option B (

\frac{\mathrm{\pi}}{6}

) is correct because the integral can be solved by direct substitution and evaluating the limits.

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